Ajla Tomljanović Height: How Tall is Ajla Tomljanović?
Ajla Tomljanovi, a professional tennis player of Croatian and Australian descent, was born on May 7, 1993. On the ITF Circuit, she has won four singles matches and three doubles match. She attained a singles career-high world No. 38 ranking on February 21, 2022.
Her doubles ranking peak was at No. 47 on January 5, 2015. Tomljanovi was a skilled young athlete who teamed up with Christina McHale to win the girls’ doubles title at the 2009 Australian Open. On March 30, 2009, she attained a junior world No. 4 rating, which was a combined career high.
Before 2014, Tomljanović played for her country of birth, Croatia. She began competing for Australia at the 2014 US Open after obtaining permanent residency in Australia. For the next four years, she was required to represent Croatia at all non-Grand Slam events, until she was granted Australian citizenship in January 2018, allowing her to represent the country at all events on the WTA Tour.
Tomljanović started her 2022 season at the Adelaide International 1. She lost to the sixth seed, Sofia Kenin, in her second-round match. She led 6-3, 5-3, and had three match points, but Kenin came back and won the match in three sets.
In Sydney, she was defeated in the second round by fifth seed and eventual champion, Paula Badosa. Ranked 43 at the Australian Open, she fell in the first round to World No. 6 and eighth seed, Badosa. She reached back-to-back quarterfinals at the 2022 Wimbledon Championships defeating Alize Cornet.
How Tall is Ajla Tomljanović?
Ajla Tomljanović is 5 feet 11 inches tall.